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theorem BFO.Participant.specificallyDependentContinuant.injEq
theorem BFO.Participant.specificallyDependentContinuant.injEq
: ∀ (a a_1 : j12bzjgj.BFO.SpecificallyDependentContinuant),
  (j12bzjgj.BFO.Participant.specificallyDependentContinuant a =
      j12bzjgj.BFO.Participant.specificallyDependentContinuant a_1) =
    (a = a_1)

Published by @sam ·

View source in j12bzjgj

Definitional, with no premises to accept.