theorem BFO.Participant.genericallyDependentContinuant.injEq

theorem BFO.Participant.genericallyDependentContinuant.injEq
theorem BFO.Participant.genericallyDependentContinuant.injEq
: ∀ (a a_1 : j12bzjgj.BFO.GenericallyDependentContinuant),
  (j12bzjgj.BFO.Participant.genericallyDependentContinuant a =
      j12bzjgj.BFO.Participant.genericallyDependentContinuant a_1) =
    (a = a_1)

Published by @sam · Jul 4, 2026

View source in j12bzjgj

Definitional, with no premises to accept.